(파이썬) if문 한번 실행 후 멈춘 다음 3초 있다 재실행 하기

class RepeatedTimer(object):
    def __init__(self, interval, function, *args, **kwargs):
        self._timer    = None
        self.interval  = interval
        self.function  = function
        self.args      = args
        self.kwargs    = kwargs
        self.is_running = False
        self.start()

    def _run(self):
        self.is_running = False
        self.start()
        self.function(*self.args, **self.kwargs)

    def start(self):
        if not self.is_running:
            self._timer = Timer(self.interval, self._run)
            self._timer.start()
            self.is_running = True

    def stop(self):
        self._timer.cancel()
        self.is_running = False

Usage:

from time import sleep

def hello(name):
    print "Hello %s!" % name

print "starting..."
rt = RepeatedTimer(1, hello, "World") # it auto-starts, no need of rt.start()
try:
    sleep(5) # your long-running job goes here...
finally:
    rt.stop() # better in a try/finally block to make sure the program ends!

https://stackoverflow.com/questions/474528/what-is-the-best-way-to-repeatedly-execute-a-function-every-x-seconds

from datetime import datetime


colliderect_time = datetime.now()

if pygame.Rect.colliderect(charac_rect,blockob22):
    colliderect_time_last = datetime.now()
    elapsed_time = (colliderect_time_last - colliderect_time).total_seconds()
    if elapsed_time > 3:
        life -= 1
        colliderect_time = datetime.now()